Three forces are acting on the ring as shown in the figure. What is the magnitude and direction of the net force acting on the ring?
Three forces are acting on the ring as shown in the figure. What is the magnitude and direction of the net force acting on the ring?
Answer:
The magnitude and direction of the net force acting on the ring is equal to the vector sum of the three forces acting on it. Based on the figure, the net force acting on the ring is equal to the vector sum of F1 minus F2 plus F3, and its magnitude is equal to the square root of (F1^2 + F3^2) minus (F2^2). The direction of the net force is the same as that of F1 minus F2 plus F3. This is because the three forces, F1, F2, and F3, all act concurrently and will add up to produce a single resultant, or net force.
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